From a batch of 20 components a sample of 6 is randomly selected without replacement for inspection. If there are 5 defective components in the batch, what is the probability that a sample contains1. exactly 1 defective?2. at least 1 defective?3. all five defectives?67646901.2.3. P(getting exactly 1 defective)=P(getting atleast one defective)defective) = 1- 6 * = 1- =P(getting all 5 defective) = 6 6 * * = 0.35595703125= 1- P(getting no0.822021484375*…




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